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Here is the algorithm Here is the code snippet
 public static bool ArmstrongNumber(int no)
        {
            //Get the number and its length
            string number = no.ToString();
            int result = 0;
            //Get the length
            int len = number.Length;
            //Declare the array size
            int[] store = new int[number.Length];
            for (int i = 0; i < len; i++)
            {
                //Get the value and parse it to double (used by Math.pow())
                double value = double.Parse(number.Substring(i, 1));
                double power = double.Parse(len.ToString());
                //Power of the Value
                store[i] = int.Parse(Math.Pow(value, power).ToString());
            }

            //Retrive all the value from array
            for (int i = 0; i < store.Length; i++)
            {
                result = result + store[i];
            }

            //If the added value and actual value are same
            if (result == no)
                return true;
            else
                return false;
        }
To calculate the Armstrong number from 1 to 999 or 1 to 9999, you can do the following by calling the above method
 public static void HowManyArmstrong(int number)
        {
            for (int i = 0; i <= number; i++)
            {
                if (ArmstrongNumber(i))
                    Console.WriteLine("The number " + i + " is Amstrong ");
            }
        }
Here is the output for value from 0 to 9999 Thanks, Karthik KK

Post Author: Karthik kk

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